Question

Test the divisibility of the following numbers by $2,3$ and $6$

$390612$

Answer 1

Step 1:- Check the divisibility of the number by $2$.

Divisibility rule of $2$:- A number is divisible by $2$ if its one digits is $0,2,4,6$ or$8.$

In the given number $390612$, one digit place is $2$.

So the number $390612$ will be divisible by $2$.

Step 2:-Check the divisibility of the number by $3$.

Divisibility rule of $3$:- A number is divisible by $3$if the sum of its digits is divisible by $3$.

Sum of the number of $390612$$=3+9+0+6+1+2=21$, Which is divisible by $3$.

The given number $390612$ will be divisible by $3$.

Step 3:-Check the divisibility of the number by $6$.

Divisibility rule of $6$:- A number is divisible by $6$ if the number is divisible by both $2$ and $3$.

The number $390612$ is divide by both $2$and $3$ so the number will be divisible by $6$.

Hence the number will be divisible by $2,3$ and $6$.