Question

Test tube (A) contains aqueous zinc acetate solution while test tube (B) contains aqueous zinc chloride solution. When $H_{2}S$ gas is passed into each solution, in (A), ZnS is precipated and in (B), HCl formed dissolved ZnS formed.
(A) : $Zn(C{H}_{3}COO{)}_2+H_{2}S⟶ZnS+C{H}_{3}COOH$
(B) : $ZnC{l}_3+H_{2}S⟶ZnS+2HCl$

If true enter 1, else enter 0.

Answer 1

In the test tube (A), zinc acetate reacts with hydrogen sulphide to form a precipitate of zinc sulphide.
$Zn(C{H}_{3}COO{)}_2+H_{2}S⟶ZnS+C{H}_{3}COOH$
In the test tube (B), zinc chloride reacts with hydrogen sulphide to form zinc sulphide which is soluble in HCl solution. Hence, no precipitate is obtained.
$ZnC{l}_3+H_{2}S⟶ZnS+2HCl$