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Question

Test whether the following relations R1, R2, and R3 are (i) reflexive (ii) symmetric and (iii) transitive:
(i) R1 on Q0 defined by (a, b) ∈ R1 ⇔ a = 1/b.
(ii) R2 on Z defined by (a, b) ∈ R2 ⇔ |a – b| ≤ 5
(iii) R3 on R defined by (a, b) ∈ R3 ⇔ a2 – 4ab + 3b2 = 0.

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Solution

(i) Reflexivity:
Let a be an arbitrary element of R1. Then,
aR1a1a for all aQ0So, R1 is not reflexive.

Symmetry:
Let (a, b) R1. Then,

a, bR1a=1bb=1ab, aR1So, R1 is symmetric.

Transitivity:
Here,
a, bR1 and b, cR2a=1b and b=1ca=11c=ca1ca, cR1 So, R1 is not transitive.

(ii)
Reflexivity:
Let a be an arbitrary element of R2. Then,
aR2 a-a=05So, R1 is reflexive.

Symmetry:
Let a, bR2a-b5b-a5 Since, a-b = b-ab, aR2So, R2 is symmetric.

Transitivity:
Let 1, 3R2 and 3, 7R21-35 and 3-75But 1-75 1,7R2So, R2 is not transitive.

(iii)
Reflexivity: Let a be an arbitrary element of R3. Then,
aR3a2-4a×a+3a2=0 So, R3 is reflexive.

Symmetry:
Let a, bR3a2-4ab+3b2=0But b2-4ba+3a20 for all a, b RSo, R3 is not symmetric.

Transitivity:
1, 2R3 and 2, 3R31-8+6=0 and 4-24+27=0But 1-12+90So, R3 is not transitive.

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