Tetra bromoethane on heating with $Z n$ gives:

Ethyl bromide

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Ethane

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Ethene

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Ethyne

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Solution

The correct option is D Ethyne
The reaction between tetra bromoethane with zinc metal is as follows:

$C H B r_{2} - C H B r_{2} + 2 Z n \to C H \equiv C H + 2 Z n B r$

Ethyne will formed, so option D is correct answer.

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Which is the correct increasing order of boiling points of the following compounds?

1-bromoethane, 1-bromopropane , 1-bromobutane, Bromobenzene

(a) Bromobenzene < 1-bromobutane < 1-bromopropane < 1-bromoethane

(b) Bromobenzene < 1-bromoethane < 1-bromopropane < 1-bromobutane

(d) 1-bromoethane < 1-bromopropane < 1-bromobutane < Bromobenze

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