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Oxidation States of Lanthanides

Tetra ethyl l...

Question

Tetra ethyl lead is prepared by using an alloy:

P b - S n

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N a - P b

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K - P b

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P b - C u

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Solution

The correct option is B $N a - P b$
Alloy of sodium and lead is used for the preparation of tetraethyl lead and tetramethyl lead. These compounds are antiknocking additives in petrol.

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Similar questions

[1] P b^{2 +} > P b^{4}, S n^{2 +} > S n^{4 +}

[2] P b^{2 +} < P b^{4}, S n^{2 +} < S n^{4 +}

[3] P b^{2 +} > P b^{4}, S n^{2 +} < S n^{4 +}

[4] P b^{2 +} < P b^{4}, S n^{2 +} > S n^{4 +}

[5] S n^{2 +} < P b^{2 +}, S n^{4 +} > P b^{4 +}

[6] S n^{2 +} < P b^{2 +}, S n^{4 +} < P b^{4 +}

Match the following.

Set -I Set -II

A) Nichrome 1) Pb, Bi,Sn,Cd

B) Type metal 2) Pb,Sb,Sn

C) Woods metal 3) Cu, Al, Zn

D) Devarda's alloy 4) Fe, Ni, Cr

P b + S n^{2 +} \to P b^{2 +} + S n

\frac{[P b^{2 +}]}{[S n^{2 +}]}

E_{c e l l} = 0

E_{P b / P b^{2 +}}^{\circ} = 0.13 v o l t

E_{S n^{2 +} / S n}^{\circ} = - 0.14 v o l t

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