Question

Tetrahedrul structure is formed by:

• A. $s{p}^2$ hybridization
• B. $s{p}^3$ hybridization
• C. $ds{p}^2$ hybridization
• D. $d^{2}s{p}^3$ hybridization

Answer 1

Answer: (B)

$s{p}^3$ hybridization

Hybridisation involves the mixing of atomic orbitals to form same number of hybrid orbitals. These hybrid orbitals are degenerate in nature or we can say that they have equal energy and the same shape. $3s+1p$ undergo hybridisation to form 4$s{p}^3$ orbitals. The regular molecular geometry with bond angle in the molecule such as $s{p}^3$ hybridisation forms tetrahedral geometry with ${109}^0{28}^{\prime }$ bond angle.