Question

${\text{2PbS + 3O}}_{\text{2}}\to 2{\text{PbO + 2SO}}_{\text{2}}$
${\text{3SO}}_{\text{2}}{\text{+ 2HNO}}_{\text{3}}{\text{+ 2H}}_{\text{2}}\text{O}\to {\text{3H}}_{\text{2}}{\text{SO}}_{\text{4}}\text{+ 2NO}$

According to the above sequence of reaction, how much ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ will be produced by 1146 gm of $PbS$?

• A. 270 g
• B. 360 g
• C. 400 g
• D. 470 g

Answer 1

The correct option is D 470 g

$2PbS+3O_2⟶2PbO+2S{O}_2$

Moles of $PbS=\frac{1146}{239}=4.8$ $moles$

$1$ $mole$ of $PbS$ gives $1$ $mole$ $S{O}_2$.

So, $4.8$ $mole$ of $PbS$ gives $4.8$ $mole$ $S{O}_2$

$\underset{4.8mole}{3S{O}_2}+2HN{O}_3+2H_{2}O⟶3H_{2}S{O}_4+2NO$

$1$ $mole$ of $S{O}_2$ gives $1$ $mole$ $H_{2}S{O}_4$

So, $4.8$ $mole$ of $S{O}_2$ gives $4.8$ $mole$ $H_{2}S{O}_4$

Mass of $H_{2}S{O}_4=98\times 4.8=470$ $g$

Hence, the correct option is $\left(D\right)$.