$A hole shaft pair s designated as 20 H_{7} f_{8} fit.$
Given that
$Upper deviation of shaft f" is - {5.5}^{0.41}$
20 mm falls in the dimension step of 18 mm and 30 mm.
$IT7 = 16 i and IT8 = 25i$
Use hole based system.
The lower and upper limits of the shaft, respectively are

19.98 & 20.02 mm

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20.00 & 20.021 mm

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19.957 & 19.98 mm

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19.947 & 19.98 mm

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Solution

The correct option is D 19.947 & 19.98 mm
19.947 & 19.98 mm

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A hole shaft pair s designated as $20 H_{7} f_{8}$ fit.
Given that
$Upper deviation of shaft f" is - {5.5}^{0.41}$
20 mm falls in the dimension step of 18 mm and 30 mm.
$IT7 = 16 i and IT8 = 25i$
Use hole based system.

The minimum clearance between the hole and shaft is

Q. A hole shaft pair has been designated as 64 mm

H_{8} f_{7}

. The diameter steps are is 50 mm and 80 mm. For shaft designation f, upper deviation is assumed as

- 5.5 D^{0.41}

\begin{matrix} For & Tolerance H_{8} & 25 i f_{7} & 16 i \end{matrix}

The limit sizes of the shaft are

Q. A hole shaft pair has been designated as 64 mm $H_8f_7$.The diameter steps are is 50 mm and 80 mm. For shaft designation f, upper deviation is assumed as $-5.5 D^{0.41}$

$\begin{array}{|l|l|l|}\hline
\text{For}&\text{Tolerance}\\\hline
H_8&25 i\\\hline
f_7& 16 i\\\hline
\end{array}$

The allowance for the above fit is

Q. The diameter of a hole is given as

50_{+ 0.00}^{+ 0.15} m m

. The upper limit on the dimensions in mm, of the shaft for achieving maximum interference of 50 microns is

Q. The fit on a hole-shaft pair system is specified as H7-h6, the type of fit is

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A hole shaft pair s designated as 20 H7 f8 fit. Given that Upper deviation of shaft f" is −5.50.41 20 mm falls in the dimension step of 18 mm and 30 mm. IT7 = 16 i and IT8 = 25i Use hole based system. The lower and upper limits of the shaft, respectively are

The correct option is D 19.947 & 19.98 mm19.947 & 19.98 mm

$A hole shaft pair s designated as 20 H_{7} f_{8} fit.$
Given that
$Upper deviation of shaft f" is - {5.5}^{0.41}$
20 mm falls in the dimension step of 18 mm and 30 mm.
$IT7 = 16 i and IT8 = 25i$
Use hole based system.
The lower and upper limits of the shaft, respectively are

The correct option is D 19.947 & 19.98 mm
19.947 & 19.98 mm