The correct option is C 2114 L
Initial volume of water=457 LVolume of water used=2314 L∴ Volume of water remaining after using:=(457−2314) L
Calculating 457−2314 we get:
Whole number part=4−2=2
Fractional part=57−314 =5×27×2−314 =1014−314 =714 =7÷714÷7 =12
Combining the whole number and the fractional parts, we get:
457−2314=212
So, the volume of water remaining inthe jug after usage is 212 L
Now, from this 212 litres, further 37litres of water are drained off.
So, the volume of water remaining afterdraining is =(212−37) L
Calculating 212−37 we get:
Whole number part=2−0=2
Fractional part=12−37 =1×72×7−3×27×2 =714−614 =(7−6)14 =114
Combining both the whole number and fractional parts, we get:
212−37=2114
∴The volume of water finally remaining in the jug is 2114 L