The correct option is A 46 MPa
Given :
P=3 kW=3000 W
N=20 rps
Form factor , y=0.3
Face width, b=36 mm
Velocity factor, Cv=1.5
Module, m=3 mm
Teeth , Z=16
Ft=2TD1
D=mZ
=3×16=48 mm
P=2πNT where N is in rps
T=P2πN=30002π×20
=23.8732 Nm
=23.8732×103 Nmm
We know
(Fd)Lewis≤Fs
Ft×Cv≤(σb.y b m)
2TD×CV=(σb)ybm
2×23.8732×103×1.548=(σb)0.3×36×3
σb=46 Nmm2
=46 MPa