Question

$\text{ABCD is a rhombus. if}\angle BCA={35}^{\circ },find\angle ADC.$

Answer 1

$\text{Given : Rhombus ABCD in which}\angle BCA={35}^{\circ }$

$\text{To find :}\angle ADC\text{Proof :}\because AD||Bc\therefore \angle DAC=\angle BCA\left(\text{Alternate}\angle s\right)But\angle BCA={35}^{\circ }\left(\text{Given}\right)\therefore \angle DAC={35}^{\circ }But\angle DAC=\angle ACD(\because AD=CD)\&\angle DAC+\angle ACD+\angle ADC={180}^{\circ }{35}^{\circ }+{35}^{\circ }+\angle ADC={180}^{\circ }\angle ADC={180}^{\circ }-{70}^{\circ }={110}^{\circ }Hence\angle ADC={110}^{\circ }$