$aFe + {bH}_{2} O \to {cFe}_{2} O_{3} + {dH}_{2}$ is a balanced equation where $a, b, c, d$ are the respective coefficients. Find the value of $a + d$ .

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Solution

The correct option is A $5$
On counting the number of atoms of all the elements on both sides of the reaction, Element Reactant Product

$Fe$ $1$ $2$

$H$ $2$ $2$

$O$ $1$ $3$

To balance the number of $Fe$ atoms, we multiply $Fe (LHS)$ by $2$ ;

$Fe$ $2$ $2$

$H$ $2$ $2$

$O$ $1$ $3$

To balance the number of $O$ atoms, we multiply $H_{2} O$ by $3$ ;

$Fe$ $2$ $2$

$H$ $6$ $2$

$O$ $3$ $3$

Lastly, to balance the number of $H$ atoms, we need to multiple $H_{2}$ by $3$ and the final equation is:
$2 Fe + 3 H_{2} O \to {Fe}_{2} O_{3} + 3 H_{2}$

Hence, $a + d = 5$


$Fe$	$1$	$2$
$H$	$2$	$2$
$O$	$1$	$3$

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aFe+bH2O→cFe2O3+dH2 is a balanced equation where a, b, c, d are the respective coefficients. Find the value of a+d.

$aFe + {bH}_{2} O \to {cFe}_{2} O_{3} + {dH}_{2}$ is a balanced equation where $a, b, c, d$ are the respective coefficients. Find the value of $a + d$ .