$An amplifier has open loop gain of A_{O L} = 5 \times 10^{3} . The amplifier is connected by the negative feedback with feedback factor β = 0.01 . If the open loop gain of op-amp decreases by 10% then the closed loop gain decreased by_____%.$
0.19

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Solution

The correct option is A 0.19
$% Change = \frac{10 %}{1 + 5 \times 10^{3} \times 10^{- 2}} = \frac{10}{51} % = 0.19 %$

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