Question

$\text{Area of the shaded regions in given figure is 25}(6-\pi )c{m}^2\text{and diameter of semicircle drawn inside the given rectangle is 10 cm. Then the shortest distance between the two semicircles in (in cm)}$

• A. 5
• B. 10
• C. 15
• D. 20

Answer 1

The correct option is A

5

Shaded area can be written as $(a.b-\pi r^2)=25(6-\pi )$, where a and b are sides of the rectangle and r is the radius of the semicircle. Here r=$\frac{a}{2}$=5 cm. Solving above equation we get b=15 cm. Hence shortest distance will be $(15-2r)=(15-2.5)=5cm$