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Question

# Area of the shaded regions in given figure is 25(6−π)cm2and diameter of semicircle drawn inside the given rectangle is 10 cm. Then the shortest distance between the two semicircles in (in cm)

A

5

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B

10

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C

15

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D

20

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Solution

## The correct option is A 5 Shaded area can be written as (a.b−πr2)=25(6−π), where a and b are sides of the rectangle and r is the radius of the semicircle. Here r=a2=5 cm. Solving above equation we get b=15 cm. Hence shortest distance will be (15−2r)=(15−2.5)=5cm

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