Question

$\text{Ball bearings are rated by a manufacturer for a life of}{10}^6\text{revolutions. The catalogue rating of a particular bearing is 16 kN. If the design load is 2 kN, the life of the bearing will be}P\times {10}^6\text{revolutions, where P is equal to}$

• A. 512

Answer 1

The correct option is A 512
$L_{10}={\left(\frac{C}{W}\right)}^3$

where

$L_{10}$= Basic life rating in millions of revolutions

$C$ = Basic dynamic load rating

$P$ = Equivalent dynamic radial load

$\therefore L_{10}={\left(\frac{16}{2}\right)}^3=512$