$Column-I$ gives certain physical terms associated with flow of current through a metallic conductor.

$Column-II$ gives some mathematical relations involving electrical quantities. Match $Column-I$ and $Column-II$ with appropriate relations.

$\begin{matrix} Column-I & Column-II (A) Drift Velocity & (P) \frac{m}{n e^{2} ρ} (B) Electrical Resistivity & (Q) n e V_{d} (C) Relaxation Period & (R) \frac{e E}{m} τ (D) Current Density & (S) \frac{E}{J} \end{matrix}$

(A)-(R), (B)-(Q), (C)-(S), (D)-(P)

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(A)-(R), (B)-(S), (C)-(P), (D)-(Q)

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(A)-(R), (B)-(S), (C)-(Q), (D)-(P)

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(A)-(R), (B)-(P), (C)-(S), (D)-(Q)

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Solution

The correct option is B $(A)-(R), (B)-(S), (C)-(P), (D)-(Q)$
Drift velocity, $V_{d} = \frac{e E τ}{m}$

Electrical resistivity, $ρ = \frac{1}{σ} = \frac{E}{J}$

Relaxation period, $τ = \frac{m}{n e^{2} ρ}$

Current density, $J = \frac{I}{A} = n e v_{d}$

Hence, option $(B)$ is correct.

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The correct option is B (A)-(R), (B)-(S), (C)-(P), (D)-(Q)Drift velocity, Vd=eEτm Electrical resistivity, ρ=1σ=EJ Relaxation period, τ=mne2ρ Current density, J=IA=nevd Hence, option (B) is correct.

The correct option is B $(A)-(R), (B)-(S), (C)-(P), (D)-(Q)$
Drift velocity, $V_{d} = \frac{e E τ}{m}$

Electrical resistivity, $ρ = \frac{1}{σ} = \frac{E}{J}$

Relaxation period, $τ = \frac{m}{n e^{2} ρ}$

Current density, $J = \frac{I}{A} = n e v_{d}$

Hence, option $(B)$ is correct.