The correct option is C ,√(11)+√(2)Given : nbsp; nbsp;5√(3), nbsp; nbsp;6√(2) Taking nbsp;5 inside the root we get √(25 ×3) = √(75) Taking 6 nbsp;i ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Surds

Compare: 5 √3...

Question

$Compare: 5 \sqrt{3}$ _____ $6 \sqrt{2}$

\sqrt{8} + \sqrt{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{7} + \sqrt{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{10} + \sqrt{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{11} + \sqrt{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D , $\sqrt{11} + \sqrt{2}$
$Given : 5 \sqrt{3}$ , $6 \sqrt{2}$
Taking 5 inside the root we get
$\sqrt{25 \times 3} = \sqrt{75}$
Taking 6 inside the root we get
$\sqrt{36 \times 2} = \sqrt{72}$
$\sqrt{75} > \sqrt{72}$

Suggest Corrections

Similar questions

Q. Compare the following pair of surds

\sqrt{25 + 36}, \sqrt{25} + \sqrt{36}

Q. Evaluate

\frac{{(36)}^{\frac{- 7}{2}} - {(36)}^{\frac{- 9}{2}}}{{(36)}^{\frac{- 5}{2}}} .

Compare: $\frac{2}{8}$ _____ $\frac{3}{5}$

Q. Compare:

21 : 23

_____

2 : 5

Join BYJU'S Learning Program

Compare: 5√3 _____ 6√2

The correct option is D ,√11+√2Given :5√3, 6√2 Taking 5 inside the root we get √25×3=√75 Taking 6 inside the root we get √36×2=√72 √75>√72

$Compare: 5 \sqrt{3}$ _____ $6 \sqrt{2}$

The correct option is D , $\sqrt{11} + \sqrt{2}$
$Given : 5 \sqrt{3}$ , $6 \sqrt{2}$
Taking 5 inside the root we get
$\sqrt{25 \times 3} = \sqrt{75}$
Taking 6 inside the root we get
$\sqrt{36 \times 2} = \sqrt{72}$
$\sqrt{75} > \sqrt{72}$