Question

$\text{Consider a hole - shaft interchangeable assembly as}40H\begin{array}{c}+0.02\\ 0.000\end{array}j\begin{array}{c}+0.01\\ -0.01\end{array}\text{.}$
$\text{The allowance (in microns) in the assembly is}$

• A. 0.01
• B. 90
• C. 10
• D. 18

Answer 1

The correct option is C 10

As clearly seen in the figure,


Allowance = difference between MML of hole and shaft

$={\text{(upper limit)}}_{shaft}-{\text{(lower limit)}}_{hole}$

$=0.01-0.00=0.01mm=10\mu m$