Question

$\text{Construct a}\Delta ABC\text{whose perimeter is 11.6cm and the base angles are}{45}^{\circ }and{60}^{\circ }$

Answer 1

Steps of construction:
1. Draw a line segment PQ = 11.6 cm.
2. Construct an angle of 45° and bisect it to get ∠ QPX.
3. Construct an angle of 60° and bisect it to get ∠ PQY.
4. The ray XP and YQ intersect at A.
5. Draw the right bisectors of A P and AQ, cutting PQ at B and C, respectively.
6. Join AB and AC .
Thus, △ ABC is the required triangle.