Divide-10a-3b - 14ab-3-by-ab-5a-2 - 7b-2-2-5a-2 - 7b-2-2-7a-2 - 5b-2-2-5a-2 - 7b-2-

The correct option is B 2(5a^2 7b^2)Given, the expression is (10a^3b 14ab^3)/ab. Taking 2ab common from the numerator, we get (10a^3b 14ab^3)/ab =2ab(5a^ ...

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Standard VIII

Mathematics

Divide (10a^3...

Question

$Divide (10 a^{3} b - 14 a b^{3}) by a b .$

(5 a^{2} - 7 b^{2})

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2 (5 a^{2} - 7 b^{2})

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2 (7 a^{2} - 5 b^{2})

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2 (5 a^{2} + 7 b^{2})

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Solution

The correct option is B $2 (5 a^{2} - 7 b^{2})$
Given, the expression is
$\frac{(10 a^{3} b - 14 a b^{3})}{a b} .$
Taking 2ab common from the numerator, we get
$\frac{(10 a^{3} b - 14 a b^{3})}{a b}$
$= \frac{2 a b (5 a^{2} - 7 b^{2})}{a b}$
$= 2 (5 a^{2} - 7 b^{2})$

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Standard VIII Mathematics

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Divide (10a3b−14ab3) by ab.

The correct option is B 2(5a2−7b2)Given, the expression is (10a3b−14ab3)ab. Taking 2ab common from the numerator, we get (10a3b−14ab3)ab =2ab(5a2−7b2)ab =2(5a2−7b2)

$Divide (10 a^{3} b - 14 a b^{3}) by a b .$

The correct option is B $2 (5 a^{2} - 7 b^{2})$
Given, the expression is
$\frac{(10 a^{3} b - 14 a b^{3})}{a b} .$
Taking 2ab common from the numerator, we get
$\frac{(10 a^{3} b - 14 a b^{3})}{a b}$
$= \frac{2 a b (5 a^{2} - 7 b^{2})}{a b}$
$= 2 (5 a^{2} - 7 b^{2})$