$Divide m^{2} + 7 m - 60 by (m - 5) .$

4(m - 6)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2(m + 6)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(m + 12)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(m - 12)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
(m + 12)

Given, the expression is
$\frac{m^{2} + 7 m - 60}{(m - 5)} .$
Now, comparing the numerator with the identity $x^{2} + (a + b) x + a b$
We note that,
$(a + b) = 7 a n d a b = - 60.$
So,
$12 + (- 5) = 7 a n d (12) (- 5) = - 60$ .
Hence,
$m^{2} + 7 m - 60 = m^{2} + 12 m - 5 m - 60 = m (m + 12) - 5 (m + 12) = (m - 5) (m + 12)$
Therefore,
$\frac{m^{2} + 7 m - 60}{(m - 5)} = \frac{(m - 5) (m + 12)}{(m - 5)} = (m + 12)$

Suggest Corrections

Similar questions

Divide (m^{2} + 7 m - 60) by (m + 12) .

Factorising $m^{2} + 7 m - 60$ and dividing it by $(m - 5)$ gives ___

$Divide m^{2} + 7 m - 60 by (m - 5) .$

Divide (m^{2} + 7 m - 60) by (m + 12) .

Factorising $m^{2} + 7 m - 60$ and dividing it by $(m - 5)$ gives:

Join BYJU'S Learning Program