Question

$\text{Divide the sum of}\frac{3}{7}\text{and}\frac{-5}{14}by-\frac{1}{2}.$

Answer 1

$\left[\begin{array}{c}\frac{3}{7}+\left(\frac{-5}{14}\right)\end{array}\right]÷\frac{-1}{2}\therefore \text{LCM of 7 and 14=14}=\left[\begin{array}{c}\frac{3}{7}\times \frac{2}{2}-\frac{5}{14}\end{array}\right]÷\frac{-1}{2}=\left[\begin{array}{c}\frac{6-5}{14}\end{array}\right]÷\frac{-1}{2}=\frac{1}{14}\times \frac{-2}{1}=\frac{1\times (-1)}{7\times 1}=\frac{-1}{7}$