Divide z5 z2-80 by 5 zz-4-A- z-16B- z-16C- z-4D- z-4

The correct option is C (z 4)Given, the expression is nbsp; z(5z^2 80)/5z(z+4). Now, the numerator can be factorized as, z(5z^2 80) =5z(z^2 16) =5z(z^2 4 ...

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Standard VIII

Mathematics

Division of an Expression by a Expression

Divide z5 z2-...

Question

$Divide z (5 z^{2} - 80) by 5 z (z + 4) .$

(z - 16)

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(z + 16)

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(z - 4)

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(z + 4)

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Solution

The correct option is C $(z - 4)$
Given, the expression is
$\frac{z (5 z^{2} - 80)}{5 z (z + 4)} .$
Now, the numerator can be factorized as,
$z (5 z^{2} - 80)$
$= 5 z (z^{2} - 16)$
$= 5 z (z^{2} - 4^{2})$
$[Using identity: a^{2} - b^{2} = (a + b) (a - b)]$
$= 5 z (z + 4) (z - 4)$
Therefore,
$\frac{z (5 z^{2} - 80)}{5 z (z + 4)} = \frac{5 z (z - 4) (z + 4)}{5 z (z + 4)} = (z - 4)$

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Similar questions

Q. Which of the following is the remainder

z (5 z^{2} - 80)

is divided by 5z(z-4)

Q. Which of the following is the remainder when

z ({5 z}^{2} - 80)

is divided by

5 z (z - 4)

Q. If

x = 2, y = 5 a n d z = 4

Find the value of:

z^{x} \times y

₹ 80 = x notes of ₹ 20
₹ 80 = y notes of ₹ 5
₹ 80 = z notes of ₹ 2

Which of the following are the values of x, y and z?

Q. If the polynomials az³ + 4z² + 3z − 4 and z³ − 4z + a leave the same remainder when divided by z − 3, find a.

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Divide z(5z2−80) by 5z(z+4).

The correct option is C (z−4)Given, the expression is z(5z2−80)5z(z+4). Now, the numerator can be factorized as, z(5z2−80) =5z(z2−16) =5z(z2−42) [Using identity: a2−b2=(a+b)(a−b)] =5z(z+4)(z−4) Therefore, z(5z2−80)5z(z+4)=5z(z−4)(z+4)5z(z+4)=(z−4)

$Divide z (5 z^{2} - 80) by 5 z (z + 4) .$