$Each of the two equal sides of an isosceles right triangle is 10 cm long. Its area is (a) 5 \sqrt{10} c m^{2} (b) 50 c m^{2} (c) 10 \sqrt{3} c m^{2} (d) 75 c m^{2}$

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Solution

Here,

Base b = 10 cm

Height h = 10 cm

Area of the triangle = 0.5 x b x h

= 0.5 x 10 x 10

= 50 $c m^{2}$

option B

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