Question

$\text{Each of the two equal sides of an isosceles right triangle is 10 cm long. Its area is}\left(a\right)5\sqrt{10}c{m}^2\left(b\right)50c{m}^2\left(c\right)10\sqrt{3}c{m}^2\left(d\right)75c{m}^2$

Answer 1

Here,

Base b = 10 cm

Height h = 10 cm

Area of the triangle = 0.5 x b x h

= 0.5 x 10 x 10

= 50 $c{m}^2$

option B