$Each side of an equilateral triangle measures 8 cm. The area of the triangle is (a) 8 \sqrt{3} c m^{2} (b) 16 \sqrt{3} c m^{2} (c) 32 \sqrt{3} c m^{2} (d) 48 c m^{2}$

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Solution

semi perimeter = $\frac{(8 + 8 + 8)}{2}$ = 12 cm

By Heron' Formula
area = $\sqrt{[s (s - a) (s - b) (s - c)]}$
= $\sqrt{[12 \times 4 \times 4 \times 4]}$
=16√3 cm²
option b is correct

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Each side of an equilateral triangle measures 8 cm. The area of the triangle is(a) 8√3 cm2 (b) 16√3 cm2 (c) 32√3 cm2 (d) 48 cm2

semi perimeter =(8+8+8)2 = 12 cm By Heron' Formula area =√[s(s−a)(s−b)(s−c)] =√[12×4×4×4] =16√3 cm² option b is correct

$Each side of an equilateral triangle measures 8 cm. The area of the triangle is (a) 8 \sqrt{3} c m^{2} (b) 16 \sqrt{3} c m^{2} (c) 32 \sqrt{3} c m^{2} (d) 48 c m^{2}$

semi perimeter = $\frac{(8 + 8 + 8)}{2}$ = 12 cm

By Heron' Formula
area = $\sqrt{[s (s - a) (s - b) (s - c)]}$
= $\sqrt{[12 \times 4 \times 4 \times 4]}$
=16√3 cm²
option b is correct