$Equations y = 3 x + 2 and y = 2^{x} that represents$ two functions. has(ve) an exponential form.

y = 2^{x}

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Both

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y = 3x + 2

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Solution

The correct option is A $y = 2^{x}$
$Let us consider the equation y = 3 x + 2$

It is in the form of equation y = mx + c, where m = slope, c is y-intercept

$The constant rate of change (slope) = 3$

A function is said to be linear if it has constant rate of change

So, y = 3x + 2 is a linear function

$Let us consider the equation y = 2^{x}$

$It is represented in the form of$
$y = a \times b^{x}$

x y

1 2

2 4

3 8

The difference of value y is not constant.

Therefore, it has no constant rate of change

$So, y = 2^{x} represents a exponential form$

The graphs of the two functions are represented as:

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