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B
x+2(sin2x2+sin4x4+sin6x6+sin8x8)+C
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C
14loge∣∣∣tanx2sin9x∣∣∣+C
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D
12loge∣∣∣tanx2sin9x∣∣∣+C
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Solution
The correct option is Bx+2(sin2x2+sin4x4+sin6x6+sin8x8)+C ∫sin9xsinxdx=∫(sin9x−sin7x)+(sin7x−sin5x)+⋯+(sin3x−sinx)+(sinx)sinxdx=x+2(sin2x2+sin4x4+sin6x6+sin8x8)+C