Expand: (x+1x)2
x2−1x2+2
x2+1x2−2
x2+1x2+2
x2+1x+2
Using the identity, (a+b)2=a2+b2+2ab we get, (x+1x)2 = x2+(1x)2+2×x×1x =x2+1x2+2
limx→0√1+x+x2−√x+12x2
If dividend = x4+x3−2x2+x+1, divisor = x - 1 and remainder = 2. Find the quotient q(x).
Multiply (x + 1) and 2x: