wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorise: 12xy8x+9y6

A
(3y2)(4x+3)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(3y2)(4x3)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(3y+2)(4x+3)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(3y2)(3x+2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A (3y2)(4x+3)
Given expression: 12xy8x+9y6

Taking 4x common from the first two terms and 3 common from the last two terms, we get

12xy8x+9y6=4x(3y2)+3(3y2)=(3y2)(4x+3)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factorisation by Grouping Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon