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Question

Factorise: 25+70x+49x2


A

(5x+7)(5x+2)

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B

(7x+5)(5x+3)

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C

(7x+5)(7x+5)

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D

(3x+7)2

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Solution

The correct option is C

(7x+5)(7x+5)


The given expression can be rewritten as,
49x2+70x+25

Using the identity: (a+b)2=a2+2ab+b2,we get

49x2+70x+25=(7x)2+2(5)(7x)+52
=(7x+5)2
=(7x+5)(7x+5)

25+70x+49x2=(7x+5)(7x+5)


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