wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorise a2bb3. Using this result, find the value of 1012×1001003

Open in App
Solution

a2bb3b(a2b2)b(a+b)(ab)Now,1012×1001003=100(10121002)=100(101+100)(101100)=100(201)(1)=20100


flag
Suggest Corrections
thumbs-up
12
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Method of Common Factors
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon