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Question

Factorise the expression 15a3b+35ab3.

A
5a(3a2b+7b3)
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B
5ab(3a2+7b2)
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C
5b(3b2a7a3)
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D
3b(5b2a7a3)
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Solution

The correct option is B 5ab(3a2+7b2)
Given, the expression is 15a3b + 35ab3.

On writing each term as the product of irreducible factors, we get,
15a3b = 3×5×a×a×a×b
35ab3 = 5×7×a×b×b×b

By taking out the common factors, we get,
15a3b+35ab3=5ab(3a2+7b2)

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