The correct option is B 5ab(3a2+7b2)
Given, the expression is 15a3b + 35ab3.
On writing each term as the product of irreducible factors, we get,
15a3b = 3×5×a×a×a×b
35ab3 = 5×7×a×b×b×b
By taking out the common factors, we get,
15a3b+35ab3=5ab(3a2+7b2)