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Question

Factorise the expression: 16y2z+20z3

A
4z(y2+5z2)
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B
4z(4y2+5z2)
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C
4z(4y25z2)
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D
4z(4y2+5z2)
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Solution

The correct option is D 4z(4y2+5z2)
Given, the expression is 16y2z+20z3.

On factorizing the terms individually,16y2z=2×2×2×2×y×y×z20z3=2×2×5×z×z×z

The common factors are 2,2 and z.

Therefore,16y2z+20z3
=(2×2×2×2×y×y×z)+(2×2×5×z×z×z)=(2×2×z)[(2×2×y×y)+(5×z×z)]=4z(4y2+5z2)

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