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Question

Factorise the expression: 2xy+3x+2y+3.

A
(2x+3)(y+1)
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B
(x+1)(2y+3)
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C
(x+1)(2y+1)
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D
(2x+1)(2y+3)
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Solution

The correct option is B (x+1)(2y+3)
Given, the expression is 2xy+3x+2y+3.

Taking x common from the first two terms and 1 common from the last two terms, we get

2xy+3x+2y+3=x(2y+3)+1(2y+3)=(x+1)(2y+3)

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