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Question

Factorise the expression: z19+19xyxyz

A
(1xy)(z19)
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B
(1xy)(z+19)
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C
(1+xy)(z19)
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D
(1+xy)(z+19)
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Solution

The correct option is A (1xy)(z19)
Given expression : z19+19xyxyz

Taking '1' common from the first two terms and '-xy' common from the last two terms, we get

z19+19xyxyz=1(z19)xy(19+z)=1(z19)xy(z19)=(1xy)(z19)

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