Question

$\text{Factorise the following by splitting the}\text{middle term and find the roots.}2x^2+x–6=0$

• A. $x=2orx=-\frac{3}{2}$
• B. $x=-2orx=\frac{3}{2}$
• C. $x=-2orx=-\frac{3}{2}$
• D. $x=2orx=\frac{3}{2}$

Answer 1

The correct option is B

$x=-2orx=\frac{3}{2}$

$\text{Given,}2x^2+x-6=0$

$2x^2+x-6=2x^2+4x-3x-6=2x(x+2)-3(x+2)=(x+2)(2x-3)$

$2x^2+x-6=0$
$\Rightarrow (x+2)(2x-3)=0$

$\therefore x+2=0or2x-3=0\Rightarrow x=-2orx=\frac{3}{2}$