Factorise-xy2-xz2-Hence- find the value of - i-9- 82-9- 22- ii-40- 5-52-40- 4-52

Xy^2 xz^2=x(y^2 z^2)=x(y z)(y+z) (i) 9× 8^2 9× 2^2=9(8^2 2^2) =9(8 2)(8+2)=9(6)(10)=540 (ii) 40× 5.5^2 40× 4.5^2=40(5.5)^2 (4.5)^2 =40(5.5 4.5)(5.5+4.5) =4 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Factorisation by Regrouping Terms

Factorise xy2...

Question

$Factorise x y^{2} - x z^{2}, Hence, find the value of : (i) 9 \times 8^{2} - 9 \times 2^{2} (i i) 40 \times {5.5}^{2} - 40 \times {4.5}^{2}$

Open in App

Solution

$x y^{2} - x z^{2} = x (y^{2} - z^{2}) = x (y - z) (y + z) (i) 9 \times 8^{2} - 9 \times 2^{2} = 9 (8^{2} - 2^{2}) = 9 (8 - 2) (8 + 2) = 9 (6) (10) = 540 (i i) 40 \times {5.5}^{2} - 40 \times {4.5}^{2} = 40 (5.5)^{2} - (4.5)^{2} = 40 (5.5 - 4.5) (5.5 + 4.5) = 40 (1) (10) = 400$

Suggest Corrections

Similar questions

Factorise

x y^{2} - x z^{2}

, Hence, find the value of

40 \times {5.5}^{2} - 40 \times {4.5}^{2}

Q. Factorise

x y^{2} - x z^{2}

. Hence, find the value.

The value of

9 \times 8^{2} - 9 \times 2^{2}

is 540.
If true then enter

1

and if false then enter

0

Q. The value of

40 \times {5.5}^{2} - 40 \times {4.5}^{2}

is equal to

$40 \times {5.5}^{2} - 40 \times {4.5}^{2}$ ___

Using the factorisation of $x y^{2} - x z^{2}$ , evaluate the value of $6 \times 3^{2} - 6 \times 2^{2}$ .

Join BYJU'S Learning Program

Factorise xy2−xz2, Hence, find the value of :(i) 9×82−9×22(ii) 40×5.52−40×4.52

xy2−xz2=x(y2−z2)=x(y−z)(y+z)(i) 9×82−9×22=9(82−22)=9(8−2)(8+2)=9(6)(10)=540(ii) 40×5.52−40×4.52=40(5.5)2−(4.5)2=40(5.5−4.5)(5.5+4.5)=40(1)(10)=400

$Factorise x y^{2} - x z^{2}, Hence, find the value of : (i) 9 \times 8^{2} - 9 \times 2^{2} (i i) 40 \times {5.5}^{2} - 40 \times {4.5}^{2}$

$x y^{2} - x z^{2} = x (y^{2} - z^{2}) = x (y - z) (y + z) (i) 9 \times 8^{2} - 9 \times 2^{2} = 9 (8^{2} - 2^{2}) = 9 (8 - 2) (8 + 2) = 9 (6) (10) = 540 (i i) 40 \times {5.5}^{2} - 40 \times {4.5}^{2} = 40 (5.5)^{2} - (4.5)^{2} = 40 (5.5 - 4.5) (5.5 + 4.5) = 40 (1) (10) = 400$