$Find the factors of (a x + b y + b x + a z + a y + b z) .$

(b x c + a y), (a x + b y)

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(a + b), (2 x + 2 y + 2 z)

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(x + y + z), (a + b)

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(b c + a x y), (a + b y)

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Solution

The correct option is C $(x + y + z), (a + b)$
$Given expression: a x + b y + b x + a z + a y + b z$

$a x + b y + b x + a z + a y + b z = (a x + a y + a z) + (b x + b y + b z)$

$Taking 'a' common from the first group and 'b' common from the second group, we get = a (x + y + z) + b (x + y + z)$

$= (x + y + z) (a + b)$

$Thus, the factors of (a x + b y + b x + a z + a y + b z) are (x + y + z) and (a + b) .$

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