Question

$\text{Find the factors of}(ax+by+bx+az+ay+bz).$

• A. $(bxc+ay),(ax+by)$
• B. $(a+b),(2x+2y+2z)$
• C. $(x+y+z),(a+b)$
• D. $(bc+axy),(a+by)$

Answer 1

The correct option is C $(x+y+z),(a+b)$

$\text{Given expression:}ax+by+bx+az+ay+bz$

$ax+by+bx+az+ay+bz=(ax+ay+az)+(bx+by+bz)$

$\text{Taking (a) common from the first}\text{group and (b) common from the}\text{second group, we get}=a(x+y+z)+b(x+y+z)$

$=(x+y+z)(a+b)$

$\text{Thus, the factors of}(ax+by+bx+az+ay+bz)\text{are}(x+y+z)\text{and}(a+b).$