Find the product of (7x−4y) and (3x−7y).
21x2 + 28y2 + 61xy
21x2 - 28y2 - 61xy
21x2 + 28y2 - 61xy
21x2 + 28y2 - 37xy
(7x−4y)(3x−7y) By applying Distributivity property, we get (7x−4y)(3x−7y) =(7x×3x)+(7x×(−7y))+((−4y)×(3x))+((−4y)×(−7y))
=21x2−49xy−12xy+28y2
=21x2 + 28y2−61xy
The product of 7x−4y and 3x−7y is
The product of (7x−4y) and (3x−7y) is: