${Findtheproductofallthezeroesofthecubicpolynomial3x}^{3} - 5 x^{2} + 8 x - 12 .$

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Solution

Find the product of zeroes:
Here, the polynomial is $3 x^{3} - 5 x^{2} + 8 x - 12 .$
Then, $a = 3; b = - 5; c = 8; d = - 12$
Product of zeroes of cubic polynomial $= \frac{- d}{a}$
$= \frac{12}{3} = 4$
Thus, the product of all the zeroes is 4

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Similar questions

Given that $x - \sqrt{5}$ is a factor of the cubic polynomial $x^{3} - 3 \sqrt{5} x^{2} + 13 x - 3 \sqrt{5}$ find all the zeroes of the polynomial.

- \frac{1}{3}

f (x) = 3 x^{3} - 5 x^{2} - 11 x - 3

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f (x) = x^{3} - 8 x^{2} + 19 x - 12

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3 x^{3} - 5 x^{2} - 11 x - 3

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