$Find the sum of$
$(11 x^{2} - 8 x + 4) and (6 x^{2} + 7 x - 10) .$

$17 x^{2} - x - 6$

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$17 x^{2} - x + 6$

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$17 x^{2} + x - 6$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$18 x^{2} - x - 6$

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Solution

The correct option is A
$17 x^{2} - x - 6$

$To find : Sum of (11 x^{2} - 8 x + 4) and (6 x^{2} + 7 x - 10)$

On adding the like terms together, we get,

$11 x^{2} - 8 x + 4$
$+ 6 x^{2} + 7 x - 10 - ---------------- -$
$17 x^{2} - x - 6$

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Similar questions

The sum of $11 x^{2} - 8 x + 4$ and $6 x^{2} + 7 x - 10$ is:

Add: $11 x^{2} - 8 x + 4$ and $6 x^{2} + 7 x - 10$ .

11 x^{2} - 8 x + 4

6 x^{2} + 7 x - 10

Multiplying $x$ with the sum of $11x^2-8x+4$ and $6x^2+7x-10$ gives:

If x is multiplied with the sum of 11 x^{2} - 8 x + 4

and 6 x^{2} + 7 x - 10, then find the product.

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