Question

$\text{Find the value of}\frac{{38}^2-{22}^2}{16},\text{using a suitable identity.}$

Answer 1

$\text{Since}{a}^2-b^2=(a+b)(a-b),\text{therefore}$

${38}^2-{22}^2=(38-22)(38+22)$

$=16\times 60$

$\text{So,}\frac{{38}^2-{22}^2}{16}=\frac{16\times 60}{16}$

$=60$