Question

$\text{Find the value of:}\frac{1}{7}+(\frac{6}{7}+1)+(\frac{4}{2}+\frac{1}{3})+\frac{11}{3}$

• A. 7

Answer 1

The correct option is A 7
$\text{Given:}\frac{1}{7}+(\frac{6}{7}+1)+(\frac{4}{2}+\frac{1}{3})+\frac{11}{3}$

$\text{We know that, by associative property of}\text{addition,}a+(b+c)=(a+b)+c.$

$\text{By applying this property, we get,}(\frac{1}{7}+\frac{6}{7})+1+\frac{4}{2}+(\frac{1}{3}+\frac{11}{3})=\frac{7}{7}+1+2+\frac{12}{3}=1+1+2+3=7$