Given, A B×A B –––––––– 6 A B ––––––––
i.e. AB×AB=6ABHere, B×B is a number whose units digit is B.Therefore, B=0,1,5 or 6
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Again, AB×AB=6AB⋯(i)⇒Then square of a two-digit number is a three-digit number.So, A can take values 1, 2 and 3.
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For A=1,2,3 and B=0,1 or 6, Eq. (i) is not satisfied.We find that A=2,B=5, satisfies the Eq. (i).
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Hence, A=2,B=5.