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Question

Find the value of the letters in the following question:

A B×A B –––––– 6 A B ––––––
[3 marks]


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Solution

Given, A B×A B –––––– 6 A B ––––––

i.e. AB×AB=6ABHere, B×B is a number whose units digit is B.Therefore, B=0,1,5 or 6
[1 mark]
Again, AB×AB=6AB(i)Then square of a two-digit number is a three-digit number.So, A can take values 1, 2 and 3.
[1 mark]
For A=1,2,3 and B=0,1 or 6, Eq. (i) is not satisfied.We find that A=2,B=5, satisfies the Eq. (i).
[1 mark]
Hence, A=2,B=5.

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