Find the value of X-234-3112-116-X

First, we calculate the value of X: X=234+3112 116 =((4× 2)+34)+((12× 3)+112) ((6× 1)+16) =114+3712 76 =11× 34× 3+3712 7× 26× 2 =3312+3712 1412 =33+37 141 ...

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Standard VI

Mathematics

Distributivity

Find the valu...

Question

$Find the value of X :$

$2 \frac{3}{4} + 3 \frac{1}{12} - 1 \frac{1}{6} = X$

4 \frac{1}{3}

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4 \frac{2}{3}

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4 \frac{1}{6}

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4 \frac{1}{12}

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Solution

The correct option is B $4 \frac{2}{3}$
$First, we calculate the value of X :$

$X = 2 \frac{3}{4} + 3 \frac{1}{12} - 1 \frac{1}{6}$

$= (\frac{(4 \times 2) + 3}{4}) + (\frac{(12 \times 3) + 1}{12}) - (\frac{(6 \times 1) + 1}{6})$

$= \frac{11}{4} + \frac{37}{12} - \frac{7}{6}$

$= \frac{11 \times 3}{4 \times 3} + \frac{37}{12} - \frac{7 \times 2}{6 \times 2}$

$= \frac{33}{12} + \frac{37}{12} - \frac{14}{12}$

$= \frac{33 + 37 - 14}{12}$

$= \frac{56}{12}$

$= \frac{56 \div 4}{12 \div 4}$

$= \frac{14}{3}$

$Now, 143 can be converted to a mixedfraction using the formula:$

$M i x e d F r a c t i o n = Q u o t i e n t \frac{R e m a i n d e r}{D i v i s o r}$

$⟹ \frac{14}{3} = 4 \frac{2}{3}$

$∴ X = 4 \frac{2}{3}$

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Find the value of X: 234+3112−116=X

$Find the value of X :$

$2 \frac{3}{4} + 3 \frac{1}{12} - 1 \frac{1}{6} = X$