Find the value of x if x if |x+2|= 3
1
5
-1
-5
|x+2| = 3
⇒ x+2 = 3 or x+2 = -3
⇒ x = 1or x = -5
The expansion of (x+y)3 is
(2x−3y)3+(x+3y)3+3(2x−3y)2(x+3y)+3(2x−3y)(x+3y)2=